FIRST Robotic Competition - Training Curriculum - Electricity Analogy and Power
Analogy to Water
The classic analogy to electricity is to water.
With that analogy there are reasonably good analogs to
many of the measurements of devices of electronics.
- Wires vs Pipes
Electric flow is constrained to wires.
But the analogy breaks down if you let the water leave
the pipe system.
Instead we will think of closed loop systems.
- Switches vs Valves
A switch can either block flow or allow it to go.
A valve can work similarly.
However opening a water valve half way is not similar to a switch.
- Voltage vs Water Pressure
As voltage goes up, the electric current goes up.
This is quite similar to water pressure.
- Current vs Water Flow
Water flow rate is quite similar to electric current.
- Resistors vs Constrictions
Either a constriction or a blockage in a water pipe will
reduce the flow. This can be overcome with higher pressure.
Similarly you can maintain an electrical current by
increasing voltage.
And you can measure a pressure difference across a
constriction, similarly to measuring a voltage difference
across a resistor.
- Battery vs Pump
A pump can be used to keep water flowing in a system.
For our purposes it is best to imagine a closed system,
with no open pipes.
The water pressure is low on the input side of the pump
and high on the output side.
A battery similarly provides a voltage difference across its terminals.
- Capacitors vs Diaphrams
If you put a rubber diaphram across a pipe it will stop
the flow. But changes in water pressure will show up
as temporary flows.
Similarly there will be an effective current thru a
capacitor, but only so long as the voltage is changing.
- AC and DC
DC is Direct Current.
It is kind of a misnomer since what is really being specified
is the voltage, not the current.
The voltage in a DC system is basically constant.
This is in contrast to an AC or Alternating Current system
where the voltage is varying regularly between positive and negative.
Ohm's Law
I will now reveal to you something that was a military
secret in World War II.
V=I*R
Voltage (V) across a resistive device is equal to
the current (I) multiplied by the resistance (R).
Amazing. It's amazing that was considered secret.
But I've never been able to fathom the military mind.
But there some fairly obvious implications.
Assume that the resistance is a constant.
(Much of the time that is a good assumption.)
- Doubling the voltage across a resistor will double its current.
- If you know the voltage across a resistor and the current
thru it you can calculate its resistance.
Power
P=V*I
Power dissipated by a resistive device is equal to the
voltage (V) across it multiplied by
the current (I).
Now I want you to combine those last two equations in order
to express power as a function of resistance and voltage.
What is striking about the result?
References
Last modified 17 Dec 2007
http://brown.armoredpenguin.com/~abrown/contact.html
http://brown.armoredpenguin.com/~abrown/first/training/Electronics/electricity.html